mil dot scope calculations
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January 30, 2016 at 6:28 pm Link
Hello guys,
I am pretty new to airguns, so I’d like to ask you a question that’s pretty silly, but please, bear with me. I’m a metric man, so I will use meters, centimeters, etc. They say that the distance between two mil dots at 100 meters is 10 centimeters on 10x power. If we put the scope on 4x, would that mean that the distance between two dots would be 40 centimeters at 100 meters? That’s probably an unlikely scenario, but I am asking out of idle curiosity. I know I could use Chairgun, but doing some math doesn’t hurt that much.Thank you and I hope you don’t mind my asking, guys. Thanks.
Hello guys, I am pretty new to airguns, so I'd like to ask you a question that's pretty silly, but please, bear with me. I'm a metric man, so I will use meters, centimeters, etc. They say that the distance between two mil dots at 100 meters is 10 centimeters on 10x power. If we put the scope on 4x, would that mean that the distance between two dots would be 40 centimeters at 100 meters? That's probably an unlikely scenario, but I am asking out of idle curiosity. I know I could use Chairgun, but doing some math doesn't hurt that much. Thank you and I hope you don't mind my asking, guys. Thanks.January 30, 2016 at 11:10 pm LinkNo, the system is inversely proportional, so 10x/4x X 10 cm=25 cm.
Reticle subtension is inversely proportional to magnification (assuming the power ring is calibrated correctly, most are close but not perfect)
No, the system is inversely proportional, so 10x/4x X 10 cm=25 cm. Reticle subtension is inversely proportional to magnification (assuming the power ring is calibrated correctly, most are close but not perfect)January 31, 2016 at 5:02 am Link“sscoyote”No, the system is inversely proportional, so 10x/4x X 10 cm=25 cm.
Reticle subtension is inversely proportional to magnification (assuming the power ring is calibrated correctly, most are close but not perfect)
Thank you, sscoyote. I think I see now. We said that 10X is the correct power for this scope (for example). Then on 6X, the distance from mil dot to mil dot would be (10X/6x)*10cm = 16.6 cm. Does that make sense?
Thank you for your time and help. I really appreciate it. Thank you.
"sscoyote"No, the system is inversely proportional, so 10x/4x X 10 cm=25 cm. Reticle subtension is inversely proportional to magnification (assuming the power ring is calibrated correctly, most are close but not perfect)
Thank you, sscoyote. I think I see now. We said that 10X is the correct power for this scope (for example). Then on 6X, the distance from mil dot to mil dot would be (10X/6x)*10cm = 16.6 cm. Does that make sense? Thank you for your time and help. I really appreciate it. Thank you. :) 
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