# Reply To: mil dot scope calculations

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January 31, 2016 at 5:02 am
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“sscoyote”No, the system is inversely proportional, so 10x/4x X 10 cm=25 cm.

Reticle subtension is inversely proportional to magnification (assuming the power ring is calibrated correctly, most are close but not perfect)

Thank you, sscoyote. I think I see now. We said that 10X is the correct power for this scope (for example). Then on 6X, the distance from mil dot to mil dot would be (10X/6x)*10cm = 16.6 cm. Does that make sense?

Thank you for your time and help. I really appreciate it. Thank you.

"sscoyote"No, the system is inversely proportional, so 10x/4x X 10 cm=25 cm. Reticle subtension is inversely proportional to magnification (assuming the power ring is calibrated correctly, most are close but not perfect)Thank you, sscoyote. I think I see now. We said that 10X is the correct power for this scope (for example). Then on 6X, the distance from mil dot to mil dot would be (10X/6x)*10cm = 16.6 cm. Does that make sense? Thank you for your time and help. I really appreciate it. Thank you. :)